Math is about computation. You will find methods and several hints which help compute quickly. Because time perform a vital part in examination. These Nominee understands more issue is a limited period can be quick attempted by computation. To compute quickly one strategy is Cube Root and Square Root. Therefore if you wish to Compute quick and precise than you must understand by heart no less than provided below Square-Root and Cube Root and try more issue in examination.

Number |
Square Root |
Number |
Square Root |

1 | 1 | 26 | 676 |

2 | 4 | 27 | 729 |

3 | 9 | 28 | 784 |

4 | 16 | 29 | 841 |

5 | 25 | 30 | 900 |

6 | 36 | 31 | 961 |

7 | 49 | 32 | 1024 |

8 | 64 | 33 | 1089 |

9 | 81 | 34 | 1156 |

10 | 100 | 35 | 1225 |

11 | 121 | 36 | 1296 |

12 | 144 | 37 | 1369 |

13 | 169 | 38 | 1444 |

14 | 196 | 39 | 1521 |

15 | 225 | 40 | 1600 |

16 | 256 | 41 | 1681 |

17 | 289 | 42 | 1764 |

18 | 324 | 43 | 1849 |

19 | 361 | 44 | 1936 |

20 | 400 | 45 | 2025 |

21 | 441 | 46 | 2116 |

22 | 484 | 47 | 2209 |

23 | 529 | 48 | 2304 |

24 | 576 | 49 | 2401 |

25 | 625 | 50 | 2500 |

Number |
Cube Root |
Number |
Cube Root |

1 | 1 | 26 | 17576 |

2 | 8 | 27 | 19683 |

3 | 27 | 28 | 21952 |

4 | 64 | 29 | 24389 |

5 | 125 | 30 | 27000 |

6 | 216 | 31 | 29791 |

7 | 343 | 32 | 32768 |

8 | 512 | 33 | 35937 |

9 | 729 | 34 | 39304 |

10 | 1000 | 35 | 42875 |

11 | 1331 | 36 | 46656 |

12 | 1728 | 37 | 50653 |

13 | 2197 | 38 | 54872 |

14 | 2744 | 39 | 59319 |

15 | 3375 | 40 | 64000 |

16 | 4096 | 41 | 68921 |

17 | 4913 | 42 | 74088 |

18 | 5832 | 43 | 79507 |

19 | 6859 | 44 | 85184 |

20 | 8000 | 45 | 91125 |

21 | 9261 | 46 | 97336 |

22 | 10648 | 47 | 103823 |

23 | 12167 | 48 | 110592 |

24 | 13824 | 49 | 117649 |

25 | 15625 | 50 | 125000 |

If you are feeling difficult to learn Square Root and Cube Root till fifty than learn at least 30. These should be at your finger tips.

There is a trick of Square Root to help you to calculate Square Root with some calculation. But the best is to learn at least fifty and to use this trick for above fifty.

__Trick for calculate Square Root__

For Example :1

(76)2

Use Formula a2+2ab+b^{2}

a2 =7*7=49

b2=6*6=36

2ab=2*7*6=84

After using formulation we will get 49,84,36

Now learn how to use this:-

We will start it from the end first will take 36 than 84 and than 49

- Put Down 6 and carry 3
- Now Add 3 in 84 we will get 3+84=87
- Put Down 7 and carry 8
- Now Add 8 in 49, we will get 8+49=57.
- And now the Square for
**76 =5776.**

For Example :2

(87)2

Use Formula a2+2ab+b^{2}

a2 =8*8=64

b2=7*7=49

2ab=2*8*7=112

After using formulation we will get 64,112,49

Now learn how to use this:-

We will start it from the end first will take 49 than 112 and than 64

- Put Down 9 and carry 4
- Now Add 4 in 112 we will get 4+112=116
- Put Down 6 and carry 11
- Now Add 11 in 64, we will get 11+64=75.
- And now the Square for
**87 =7569.**

There is one another important formula to calculate Square, use for figure, which are near & less than 100.

For Example:1

(97)2

For Calculating (97)2 follow Steps

- First we will see that 97 is how small from 100
- Answer is 3. Then we will take a Square of (3)2=9
- Put Down 9 and put one zero left to the 9
- After than we will subtract 3 from 97 i.e 97-3=94.
- And the Answer will be 9409

For Example:1

(94)2

For Calculating (94)2 follow Steps

- First we will see that 94 is how small from 100
- Answer is 6. Then we will take a Square of (6)2=36
- Put Down 36.
- After than we will subtract 6 from 94 i.e 94-6=88.
- And the Answer will be 8836.

*Algebra Formulas *

These Supplements helps a great deal to compute issues that are large in mathematics. These will be the fundamental of Mathematics and every Nominee should be proceed through with these formulations. Once you are going to understand these formulations, you will discover that how simple would be to fix large problems in mathematics with velocity and precision.

* *

*(a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab**(a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab**(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)**(a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b)**(a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b)**a2 − b2 = (a + b)(a − b)**a3 − b3 = (a − b)(a2 + ab + b2)**a3 + b3 = (a + b)(a2 − ab + b2)**an − bn = (a − b)(an−1 + an−2b + an−3b2 + ··· + bn−1)**an = a.a.a . . . n times*

*Divisible rule*

These are the guidelines to find if many may be separate with the dig it that is specified or maybe not. By using these principles you do not require to compute the integer, only recall the guideline and locate it with velocity and precision. The outcome can be found by you without resolve a problem you should just apply the principle that is divisible. Here subsequent guidelines offered below only make your computation quickly and understand these principles.

*Rule No.1*

*Any 3-digit number with sequential digits, for example:- 123, 234, 456,*

*will be divide by 3.*

*Rule No.2:- Dividing by 4*

** **See the last two digits. If the given number ,last two digits is divisible by 4, the original number will be divide by 4

**Rule No.3:-Dividing by 5**

If the last digit is a five or a zero, then the number is divisible by 5.

**Rule No.4:-***Dividing by 6*

If the given number is divisible by both 3 and 2, than the number will be divisible by 6 as well.

**Rule No.5:-Dividing by 7**

To find out whether a number is divisible by seven, take the last digit, double it, and subtract it from the rest of the number

**Rule No.6:-Dividing by 8**

To find out whether a number is divisible by 8,Check the last three digits. If the last three digits of a number are divisible by 8, then the whole number will be divide by 8.

**Rule No.7:- Dividing by 9**

Add all the digits. If that sum is divisible by nine, then the original number is as well.

**Rule No.8:-Dividing by 10**

If the number ends in 0, than the whole number is divisible by 10.

**Rule No.9:-Dividing by 11**

Let’s look at **352**, which is divisible by 11; the answer is 32. 3+2 is 5; another way to say this is that 35 -2 is 33.

Now look at **3531**, which is also divisible by 11. It is not a coincidence that 353-1 is 352 and 11 × 321 is 3531.

**Rule No.10:-Dividing by 12**

To Find out where a number is divisible by 12 or not, first divide the whole number by 3 and 4. If the number is divide by 3,4 then the whole number will be divide by 12 also.