# Maths Tips & Tricks for All IBPS Exam in 2016

Math is about computation. You will find methods and several hints which help compute quickly. Because time perform a vital part in examination. These Nominee understands more issue is a limited period can be quick attempted by computation. To compute quickly one strategy is Cube Root and Square Root. Therefore if you wish to Compute quick and precise than you must understand by heart no less than provided below Square-Root and Cube Root and try more issue in examination.

 Number Square Root Number Square Root 1 1 26 676 2 4 27 729 3 9 28 784 4 16 29 841 5 25 30 900 6 36 31 961 7 49 32 1024 8 64 33 1089 9 81 34 1156 10 100 35 1225 11 121 36 1296 12 144 37 1369 13 169 38 1444 14 196 39 1521 15 225 40 1600 16 256 41 1681 17 289 42 1764 18 324 43 1849 19 361 44 1936 20 400 45 2025 21 441 46 2116 22 484 47 2209 23 529 48 2304 24 576 49 2401 25 625 50 2500

 Number Cube Root Number Cube Root 1 1 26 17576 2 8 27 19683 3 27 28 21952 4 64 29 24389 5 125 30 27000 6 216 31 29791 7 343 32 32768 8 512 33 35937 9 729 34 39304 10 1000 35 42875 11 1331 36 46656 12 1728 37 50653 13 2197 38 54872 14 2744 39 59319 15 3375 40 64000 16 4096 41 68921 17 4913 42 74088 18 5832 43 79507 19 6859 44 85184 20 8000 45 91125 21 9261 46 97336 22 10648 47 103823 23 12167 48 110592 24 13824 49 117649 25 15625 50 125000

If you are feeling difficult to learn Square Root and Cube Root till fifty than learn at least 30. These should be at your finger tips.

There is a trick of Square Root to help you to calculate Square Root with some calculation. But the best is to learn at least fifty and to use this trick for above fifty.

Trick for calculate Square Root

For Example :1

(76)2

Use Formula a2+2ab+b2

a2 =7*7=49

b2=6*6=36

2ab=2*7*6=84

After using formulation we will get 49,84,36

Now learn how to use this:-

We will start it from the end first will take 36 than 84 and than 49

1. Put Down 6 and carry 3
2. Now Add 3 in 84 we will get 3+84=87
3. Put Down 7 and carry 8
4. Now Add 8 in 49, we will get 8+49=57.
5. And now the Square for 76 =5776.

For Example :2

(87)2

Use Formula a2+2ab+b2

a2 =8*8=64

b2=7*7=49

2ab=2*8*7=112

After using formulation we will get 64,112,49

Now learn how to use this:-

We will start it from the end first will take 49 than 112 and than 64

1. Put Down 9 and carry 4
2. Now Add 4 in 112 we will get 4+112=116
3. Put Down 6 and carry 11
4. Now Add 11 in 64, we will get 11+64=75.
5. And now the Square for 87 =7569.

There is one another important formula to calculate Square, use for figure, which are near & less than 100.

For Example:1

(97)2

1. First we will see that 97 is how small from 100
2. Answer is 3. Then we will take a Square of (3)2=9
3. Put Down 9 and put one zero left to the 9
4. After than we will subtract 3 from 97 i.e 97-3=94.
5. And the Answer will be 9409

For Example:1

(94)2

1. First we will see that 94 is how small from 100
2. Answer is 6. Then we will take a Square of (6)2=36
3. Put Down 36.
4. After than we will subtract 6 from 94 i.e 94-6=88.
5. And the Answer will be 8836.

Algebra  Formulas

These Supplements helps a great deal to compute issues that are large in mathematics. These will be the fundamental of Mathematics and every Nominee should be proceed through with these formulations. Once you are going to understand these formulations, you will discover that how simple would be to fix large problems in mathematics with velocity and precision.

1. (a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab
2. (a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab
3. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)
4. (a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b)
5. (a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b)
6. a2 − b2 = (a + b)(a − b)
7. a3 − b3 = (a − b)(a2 + ab + b2)
8. a3 + b3 = (a + b)(a2 − ab + b2)
9. an − bn = (a − b)(an−1 + an−2b + an−3b2 + ··· + bn−1)
10. an = a.a.a . . . n times

Divisible rule

These are the guidelines to find if many may be separate with the dig it that is specified or maybe not. By using these principles you do not require to compute the integer, only recall the guideline and locate it with velocity and precision. The outcome can be found by you without resolve a problem you should just apply the principle that is divisible. Here subsequent guidelines offered below only make your computation quickly and understand these principles.

Rule No.1

Any 3-digit number with sequential digits, for example:-  123, 234, 456,

will be divide by 3.

Rule No.2:- Dividing by 4

See the last two digits. If the given number ,last two digits is divisible by 4, the original number will be divide by 4

Rule No.3:-Dividing by 5

If the last digit is a five or a zero, then the number is divisible by 5.

Rule No.4:-Dividing by 6

If the given number is divisible by both 3 and 2, than the number will be divisible by 6 as well.

Rule No.5:-Dividing by 7

To find out whether a number is divisible by seven, take the last digit, double it, and subtract it from the rest of the number

Rule No.6:-Dividing by 8

To find out whether a number is divisible by 8,Check the last three digits. If the last three digits of a number are divisible by 8, then the whole number will be divide by 8.

Rule No.7:- Dividing by 9

Add all the digits. If that sum is divisible by nine, then the original number is as well.

Rule No.8:-Dividing by 10

If the number ends in 0, than the whole number is divisible by 10.

Rule No.9:-Dividing by 11

Let’s look at 352, which is divisible by 11; the answer is 32. 3+2 is 5; another way to say this is that 35 -2 is 33.

Now look at 3531, which is also divisible by 11. It is not a coincidence that 353-1 is 352 and 11 × 321 is 3531.

Rule No.10:-Dividing by 12

To Find out where a number is divisible by 12 or not, first divide the whole number by 3 and 4. If the number is divide by 3,4 then the whole number will be divide by 12 also.

Updated: 28th July 2016 — 2:36 pm
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